How do step up transformers obey the law of conservation of energy?

How do step up transformers obey the law of conservation of energy?|||For an ideal transformer:





V * A on the primary side = V * A on the secondary side.





V * A is power, which is the rate at which energy is delivered. If the rate of energy is the same on the primary and secondary, then energy is conserved.





In order for V * A to be the same on the secondary as it is on the primary and, if it is a step-up transformer, then


n * Vprimary = Vsecondary


hence, 1/n * Aprimary = Asecondary





(n * V) * (1/n * A) = n/n * V * A = V * A energy is conserved!





.|||The law of conservation of energy is that energy cannot be created or destroyed. A transformer does not make more energy,but rather it takes the voltage and raises it , this may seem to disregard the law but instead just making more it reduces the the current. As voltage increases by say 10 times the amperage 1/10 of the orginal.|||An ideal transformer neither generates nor consumes energy, so the power entering it will equal the power leaving it. Power can be computed by multiplying the RMS voltage by the RMS current. So, if an ideal transformer has an input voltage of (say) 100 V and an output voltage of 200 V, the current coming out will be exactly half the current going in. A real transformer is not ideal but dissipates power owing to the finite resistance of its windings and other effects, so if a real transformer steps up voltage from 100 V to 200 V, its output current will be less than half its input current.|||If a transformer is thrown from a tall building and it lands on a spring, then that spring will hold almost as much potential energy as the transformer did at the top of the building. Some energy will be lost to heat. This proves the law of conservation of energy.|||By using Magic